8x^2+8x=-1

Solution for 8x^2+8x=-1 equation:

8x^2+8x=-1

We move all terms to the left:

8x^2+8x-(-1)=0

We add all the numbers together, and all the variables

8x^2+8x+1=0

a = 8; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·8·1
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{2}}{2*8}=\frac{-8-4\sqrt{2}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{2}}{2*8}=\frac{-8+4\sqrt{2}}{16}
$